Solar Calculator: how much solar do you need?
Short answer: work out how many watt-hours you use per day, divide by your peak sun hours and a 25% system loss, and that gives the array size in kWp. A typical South African home using 10 kWh a day needs roughly a 2.4 kWp array (about 5 standard panels) and around 12.5 kWh of lithium battery for one day of backup.
The calculator below does this for your own appliances, and the tables further down show the common sizes so you do not have to calculate anything.
Work out your own system
Tick what you want to run, or add your own row. Leave the hours at 0 if an item should not count.
| Appliance | Watts (W) | Hours / day | Wh / day |
|---|---|---|---|
| LED lighting | 200 | ||
| Refrigerator | 1200 | ||
| Wi-Fi router | 240 | ||
| Television | 400 | ||
| Laptop | 480 | ||
| Water pump | 750 | ||
| Kettle | 500 | ||
| Washing machine | 500 | ||
| Air conditioner | 0 | ||
| Electric geyser | 0 |
Everything is calculated in your browser — nothing is sent anywhere.
Your estimated system
An estimate for budgeting, not a design. Shading, roof direction, roof angle and your actual usage all change the result — we quote against your real figures.
Get a quote for this sizeCommon solar system sizes
If you would rather read off a table than calculate, these are the sizes we are asked for most. Figures assume 5.5 peak sun hours, a 25% system loss and one day of battery backup.
| Daily use | Array size | 550 W panels | Lithium battery | Typical home |
|---|---|---|---|---|
| 3 kWh/day | 0.7 kWp | 2 | 3.8 kWh | Small flat, lights + fridge + TV |
| 5 kWh/day | 1.2 kWp | 3 | 6.3 kWh | Couple, essentials only |
| 10 kWh/day | 2.4 kWp | 5 | 12.5 kWh | Family home, no geyser on solar |
| 15 kWh/day | 3.6 kWp | 7 | 18.8 kWh | Family home with pump and TV |
| 20 kWh/day | 4.8 kWp | 9 | 25.0 kWh | Larger home, evening cooking |
| 30 kWh/day | 7.3 kWp | 14 | 37.5 kWh | Large home or small office |
How the numbers are worked out
Every figure above comes from the same four steps, so you can check it yourself:
- Daily energy — add up
watts × hoursfor everything you run. A 60 W laptop on for 8 hours is 480 Wh. - Array size — divide the daily energy by your peak sun hours and by the
system efficiency. We use 25% losses (inverter, cabling, heat, dust) as a
realistic South African figure:
kWp = daily kWh ÷ (peak sun hours × 0.75) - Battery — daily energy × days of backup, then divided by how much of the battery you may actually use: 80% for lithium, 50% for lead-acid.
- Inverter — sized from the largest simultaneous load, with 25% headroom, because motors and compressors draw several times their running current for a moment when they start.
Related: frequently asked questions · battery and solar glossary · solar panels we supply